Feedback: irt.org FAQ Knowledge Base Q1310

Feedback on:
irt.org FAQ Knowledge Base Q1310

Comments:
I use the following to trim spaces:

str.replace(/^\s*/, '').replace(/\s*$/, '');

Length:
Too short

Technical:
Just right

Comments:
We were wondering how to modify this code to check for these values (spaces, carriage returns, etc) as if a null entry -- no text, just spacing, and then return an error -- this is a required field; only spaces have been spplied.

Worth:
Very worth reading

Comments:
Hey Thanks for this....it was excellent solution for the problem.

Comments:
Reading at the documentation for RegExp I found that the replace method returns a new string. It doesn't modify the string that invokes the method.

I change the trim function to this in order to make it work:

function trim(str)
{
var newString = str.replace(/^\s*/, '').replace(/\s*$/, '');
return newString;
}