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Feedback on: irt.org FAQ Knowledge Base Q1310
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Sent by Mauricio Zuluaga on September 09, 2002 at 11:55:00:
Comments: Reading at the documentation for RegExp I found that the replace method returns a new string. It doesn't modify the string that invokes the method. I change the trim function to this in order to make it work: function trim(str) { var newString = str.replace(/^\s*/, '').replace(/\s*$/, ''); return newString; }
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