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Feedback on: irt.org FAQ Knowledge Base Q332
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Sent by Josh Hoexter on September 02, 1999 at 19:19:16:
Worth: Worth reading
Length: Just right
Technical: Just right
Comments: To check for a string that will return NaN when converting to a number: if (((contents / contents) != 1) && (contents != 0)) will not work if contents is a string containing only spaces. You need something like this: if ((contents / contents != 1) && (parseFloat(contents) != 0))
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