|
Q1071 indexOf in combination with charAt does not work
irt.org | Knowledge Base | JavaScript | Bugs | Q1071 [ previous next ] Q1071 indexOf in combination with charAt does not workSymptom: if (astring.indexOf(bstring.charAt(i)) !=-1) returns the index of the current bstring char in bstring instead of in astring.
Affects: Workaround: ch = bstring.charAt(i); if (astring.indexOf(ch) !=-1) ... |
Last Updated: 30th March 2008. Maintained by: Martin Webb and Michel Plungjan
irt.org liability, trademark, document use, privacy statement and software licensing rules apply.
irt.org liability, trademark, document use, privacy statement and software licensing rules apply.
Copyright © 1996-2008 irt.org, All Rights Reserved.